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Specific Heat Capacity

A thermos-fla...

Question

A thermos-flask of negligible heat capacity contains 100 g of ice and 30g of water. Is it possible to condense the water to ice by adding ice at 0 $^{o}$ C ? Explain giving a suitable reason to justify your answer.

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Solution

No, it is not possibke because the ice will also melt to water and thus the statement is false

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Q. A thermos-flask of negligible heat capacity contains 100 g of ice. Calculate the amount of water in the flask after condensation.

(Given that: Latent heat of ice

= 336 J g^{- 1}

, latent heat of steam

= 2260 J g^{- 1}

, specific heat capacity of water

= 4.2 J g^{- 1} C^{- 1}

Q. A vessel of negligible heat capacity contains 40g of ice at 0

^{o}

C. 8g of steam at 100

^{o}

C is passed into the ice to melt it. Find the final temperature of mixture (Latent heat of ice

= 336 J g^{- 1}

, Latent heat of steam

= 2268 J g^{- 1}

. Sp. heat capacity of water

= 4.2 J g^{- 10} C^{- 1}

Q. The temperature of

170

50^{o}

C is lowered to

5^{o}

C by adding certain amount of ice to it. Find the mass of ice added. Given: Specific heat capacity of water

= 4200

k g^{- 1}

^{0} C^{- 1}

and Specific latent heat of ice

= 336000

k g^{- 1}

Q. Which contains more heat, 1 kg of ice at 0° C or 1 kg of water at 0° C? Give reason for your answer.

500 g

100 g

0^{o} C

are in a calorimeter whose water equivalent is

40 g

10 g

100^{o} C

added to it. Then water in the calorimeter is (Latent heat of ice

= 80 c a l / g

, Latent heat of steam

= 540 c a l / g

)

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