You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Partially Inelastic Collision

A thick unifo...

Question

A thick uniform bar lies on a frictionless horizontal surface and is free to move in any way on the surface. Its, mass is $0.16 k g$ and length is $1.7 m$ . Two particles each of mass $0.08 k g$ are movingon the same surface and twards the bar in the direction perpendicular to the bar, one with a velocity of $10 m s^{- 1}$ and other with velocity $6 m s^{- 1}$ . If collision between particles and bar is completely inelastic, both particles strike with the bar simultaneously. The velocity of centre of mass after collision is

2 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

167 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $4 m s^{- 1}$
$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2} + m_{3}) v 0.08 (10 + 6) = (0.08 + 0.08 + 0.16) v v = \frac{0.08 \times 16}{0.32} v = 4 ㎧$

Suggest Corrections

Similar questions

Q. A thin uniform bar lies on a friction less horizontal surface and is free to move in any direction on the surface. Its mass is 0.16 kg and length is

\sqrt{3} m

. Two particles, each of mass is 0.08 kg are moving on the same surface and towards the bar in a direction perpendicular to the bar, one with velocity 10 ms

^{- 1}

and the other with 6 ms

^{- 1}

as shown in the Figure. The first particle strikes the bar at point A and the other at point B. Point A and B are at a distance of 0.5 m from the center of the bar. The particle strikes the bar at the same instant of time and sticks to the bar after collision. Then, the loss of kinetic energy of the system in the above collision process is :

Q. A uniform bar of length

6 a

and mass

8 m

lies on a smooth horizontal table. Two point masses

m

and

2 m

moving in opposite direction in the same horizontal plane with speed

2 v

and

v

, respectively. strike the bar and stick to the bar after collision. Calculate.
The velocity of the centre of mass after collision.

Q. A uniform bar of length

6 a

and mass

8 m

lies on a smooth horizontal table. Two point masses

m

and

2 m

moving in opposite direction in the same horizontal plane with speed

2 v

and

v

, respectively. strike the bar and stick to the bar after the collision. Calculate :
The angular velocity of the centre of mass after collision.

Q. Two particles

A

and

B

of mass

m

each and moving with velocity

v

, hit the ends of a rigid bar of the same mass

m

and length

l

simultaneously and stick to the bar as shown in the figure. The bar is kept on a smooth horizontal plane. The linear and angular speed of the system (bar

+

particle) after the collision are

A uniform bar of negligible cross sectional area of length 6a and mass 8m lies on a horizontal frictionless table. Two point masses m and 2m moving in opposite directions but in the same horizontal plane with speeds 2v and v respectively strike the bar at a distance a and 2a from one end and stick to the bar after the collision. Then, after the collision,

Join BYJU'S Learning Program

The correct option is B 4ms−1m1v1+m2v2=(m1+m2+m3)v0.08(10+6)=(0.08+0.08+0.16)vv=0.08×160.32v=4㎧

The correct option is B $4 m s^{- 1}$
$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2} + m_{3}) v 0.08 (10 + 6) = (0.08 + 0.08 + 0.16) v v = \frac{0.08 \times 16}{0.32} v = 4 ㎧$