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Question

A thick uniform rubber rope of density 1.5 g cm3 and Young's modulus 5×106 Nm2 has a length of 8m. When hung from the ceiling of a room, the increase in length of the rope due to its own weight will be

A
9.6×102
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B
19.2×102
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C
9.6×103
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D
9.6
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Solution

The correct option is D 19.2×102
The youngs modulus Y is defined as Y=FLAx , where F is force apllied , L is original length x is change in length and σ=density of the wire.
x=σL2gAY(F=mg=σ×A×L×g)
x=σL2gY=1.5×103×64×105×106=19.2×102
Therefore option B is correct

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