1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A thin circular ring of mass m and radius R is rotating about its axis with a constant angular velocity ω. Two objects each of mass M are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity ω′=

A
ωm(m+2M)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
ω(m+2m)m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
ω(m2m)(m+2m)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
ωm(m+M)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A ωm(m+2M)using conservation of Angular momentum inertia angled momentum : final Angular momentumI w′=I′w′mR2w=(mR2+MR2+MR2)w1mR2w=(mR2+2MR2)w1∴ w1=mwm+2m Answer is A

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Rotational Kinematics
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program