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Standard XII
Physics
Mechanism of Carrier Conduction
A thin conduc...
Question
A thin conducting ring of radius R is given a charge +Q. The electric field at the centre O of the ring due to the charge on the part AKB of the ring is E. The electric field at the centre due to the charge on the part ACDB of the ring is
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Q.
A thin conducting ring of radius
R
is given a charge
+
Q
uniformly distributed over its circumference. The electric field at the centre
O
of the ring due to the charge on the part
AKB
of the ring is
E
. The electric field at the centre due to the charge on the part
ACDB
of the ring is
Q.
A thin conducting ring of radius R is given a charge + Q. The electric field at the center O of the ring due to the charge on the part AKB of the ring is E. The electric field at the center due to the charge on the part ACDB of the ring is
Q.
A non conducting ring of radius
R
has uniformly distributed positive charge
Q
. A small part of the ring, of length
d
, is removed
(
d
<
<
R
)
. The electric field at the centre of the ring will now be
Q.
The electric field strength due to ring of radius R at a distance x from its centre on the axis of ring carrying charge Q is given by
E
=
1
4
π
ε
0
Q
x
(
R
2
+
x
2
)
3
/
2
. At what distance from the centre will the electric field be maximum?
Q.
Charge q is uniformly distributed over a thin half ring of radius R. The electric field at the centre of the ring is :
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