CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A thin film with an index of refraction of 1.50 coats a glass lens. The index of refraction of the glass is 1.60.
What is the thinnest coating of film that will provide for very strongly reflected 546nm light (constructive thin film interference)?

A
171nm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
182nm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
91nm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
273nm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
415nm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 182nm
Light is entering in a medium of higher refractive index (n2=1.60) from a medium of lower index (n1=1.50), therefore net path difference in the reflected rays from the two interfaces will be equal to 2t (where t is thickness of thin film) , because ,
when light goes from air to thin film path shift in reflected ray =λ/2,
when light goes from thin film to glass path shift in reflected ray =λ/2+2t
for constructive interference,
2t=mλ,
or 2t=mλ/n1 ,
where λ= wavelength in thin film ,
λ=546nm(given) wavelength in vacuum ,
for thinnest coating , m=0(minimum) ,
therefore, tmin=λ/2n1=546/(2×1.50)=182nm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Optical Path
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon