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Lens Maker's Formula

A thin lens o...

Question

A thin lens of refractive index 1.5 has a focal length of 15 cm in air. When the lens is placed in a medium of refractive index 4/3, its focal length will become

A

30 cm

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B

45 cm

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C

60 cm

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D

75 cm

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Solution

The correct option is D 60 cm
By using $\frac{f_{1}}{f_{2}} = \frac{(_{a} μ_{g} - 1)}{(_{l} μ_{g} - 1)} \Rightarrow f_{w} = 4 f_{a} = 4 \times 15 = 60 c m$

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