Question

A thin metal iron-sheet is rhombus in shape, with each of its side 10 m. If one of its diagonals is 16 m, find the cost of painting its both sides at the rate of Rs $6per{m}^2$

Answer 1

$\Rightarrow$L${}^2$=($\frac{d1}{2}$)${}^2$+($\frac{d2}{2}$)${}^2$

10${}^2$=8${}^2$+($\frac{d2}{2}$)${}^2$

d2=12 cm

Area = $\frac{1}{2}$(d1$\times$d2)

= $\frac{1}{2}$(16$\times$12)

= 96 $c{m}^2$

Cost=2(96$\times$6)

= 1152 Rs