Question

A thin prism of $5^o$ angle gives a deviation of ${1.5}^o$. What is the refractive index of the material.

Answer 1

Given angle of prism=$5^0$ and angle of deviation $\delta m$=${1.5}^0$

Refractive index of the material $\mu =\frac{\frac{sinA+\delta m}{2}}{sin\frac{A}{2}}=\frac{sin\frac{(5+1.5)}{2}}{sin\left(\frac{5}{2}\right)}=\frac{0.0567}{0.04361}=1.30$