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Question

A thin, rectangular film of liquid is extended from (2 cm×3 cm) to (4 cm×6 cm). If the work done in the process is 6×104 J, the value of surface tension of the liquid is

A
0.133 N/m
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B
0.33 N/m
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C
0.166 N/m
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D
0.12 N/m
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Solution

The correct option is C 0.166 N/m
The thin rectangular film of liquid has two surfaces (Upper and inner surfaces).
Total Initial area Ai=2×2×3 cm2=12 cm2
Total final area Af=2×4×6 cm2=48 cm2
Increase in area of film,
ΔA=(4812) cm2=36 cm2
ΔA=36×104 m2
Hence, work done during the process,
W=T×ΔA
T=WΔA=6×10436×104 N/m
T=0.166 N/m

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