A thin rectangular magnet suspended freely has a period of oscillation $4 s$ . If it is broken into two halves each having half their initial length, then when suspended similarly, the time period of oscillation of each part will be

4 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 \sqrt{2} s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $4 \sqrt{2} s$
A thin rectangular magnet suspended freely has a period of oscillation $T = 4 s$
We know that
$T = 2 π \sqrt{\frac{l}{g}} \frac{T_{1}}{T_{2}} = \sqrt{\frac{l_{1}}{l_{2}}} \frac{4}{T_{2}} = \sqrt{\frac{l_{1}}{l_{1} / 2}} = \sqrt{2} o r T_{2} = 4 \sqrt{2} s$

Suggest Corrections

Similar questions

Q. A thin rectangular bar magnet suspended freely has a period of oscillation of

4 s

. What will be the period of oscillation if the magnet is broken into two halves

(

each having half the original length

)

and one of the pieces is made to oscillate in the same field?

Q. A thin rectangular magnet suspended freely has a period of oscillation equal to

T

. Now it is broken into two equal halves (each having half of the original length) and one piece is made to oscillate freely in the same field. if its period of oscillation is

T

', the ratio

T^{'} / T

The period of oscillation of a freely suspended long bar magnet is 4 seconds. If it is cut into two equal parts lengthwise, then the time period of each part will be

Q. A thin magnetic iron rod of length

30 c m

is suspended in a uniform magnetic field. Its time period is

4 s

. If it is broken into three equal parts, the time period of oscillation of one part in seconds, when suspended in the same magnetic field is :

Q. The time period of a freely suspended magnet is

4

s. If it is broken in length into two equal parts and one part is suspended in the same way. Then its time period will be.

Join BYJU'S Learning Program

A thin rectangular magnet suspended freely has a period of oscillation 4 s. If it is broken into two halves each having half their initial length, then when suspended similarly, the time period of oscillation of each part will be

The correct option is D 4√2 sA thin rectangular magnet suspended freely has a period of oscillation T=4sWe know thatT=2π√lgT1T2=√l1l24T2=√l1l1/2=√2orT2=4√2s

A thin rectangular magnet suspended freely has a period of oscillation $4 s$ . If it is broken into two halves each having half their initial length, then when suspended similarly, the time period of oscillation of each part will be

The correct option is D $4 \sqrt{2} s$
A thin rectangular magnet suspended freely has a period of oscillation $T = 4 s$
We know that
$T = 2 π \sqrt{\frac{l}{g}} \frac{T_{1}}{T_{2}} = \sqrt{\frac{l_{1}}{l_{2}}} \frac{4}{T_{2}} = \sqrt{\frac{l_{1}}{l_{1} / 2}} = \sqrt{2} o r T_{2} = 4 \sqrt{2} s$