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Standard XII

Physics

Newton's Second Law: Rotatory Version

A thin rod of...

Question

A thin rod of length 1 m is fixed in a vertical position inside a train which is moving hirizontally with constant acceleration of 4 m/ $s^{2}$ . A bead can slide on the rod and coefficient of friction between them is $\frac{1}{2}$ . If bead is released from top at rest, then time it takes to reach the bottom is [Take g = 10 m/ $s^{2}$ ]

2 s

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4 s

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\frac{1}{2}

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\frac{1}{4}

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Similar questions

Q. A thin rod of length

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A long horizontal rod has a bead which can slide along its length, and initially placed at a distance $L$ from one end $A$ of the rod. The rod is set in angular motion about $A$ with constant angular acceleration $a$ . If the coefficient of friction between the rod and the bead is $m$ , and gravity is neglected, then the time after which the bead starts slipping is

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