A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction B as shown in the figure- At any instant- its speed is v- What is the potential difference developed across the ring at this instant -

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Standard XII

Physics

Force on a Current Element

A thin semici...

Question

A thin semicircular conducting ring of radius $R$ is falling with its plane vertical in a horizontal magnetic induction $\to B$ as shown in the figure. At any instant, its speed is $v$ . What is the potential difference developed across the ring at this instant ?

B R v

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\frac{B R v}{2}

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2 B R v

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\frac{B R v}{3}

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Solution

The correct option is C $2 B R v$

The effective length perpendicular to the magnetic field is $2 R$ .

So, induced emf,

$Δ V = B l v = B (2 R) v = 2 B R v$

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A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction →B as shown in the figure. At any instant, its speed is v. What is the potential difference developed across the ring at this instant ?

The correct option is C 2BRv The effective length perpendicular to the magnetic field is 2R. So, induced emf, ΔV=Blv=B(2R)v=2BRv

A thin semicircular conducting ring of radius $R$ is falling with its plane vertical in a horizontal magnetic induction $\to B$ as shown in the figure. At any instant, its speed is $v$ . What is the potential difference developed across the ring at this instant ?

The correct option is C $2 B R v$

The effective length perpendicular to the magnetic field is $2 R$ .

So, induced emf,

$Δ V = B l v = B (2 R) v = 2 B R v$