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Question

A thin spherical pressure vessel of 200 mm diameter and 1 mm thickness is subjected to an internal pressure varying from 4 to 8 MPa. Assume that the yield, ultimate, and endurance strength of material are 600, 800 and 400 MPa respectively. The factor of safety as per Goodman's relation is

A
1.2
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B
1.6
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C
1.4
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D
2.0
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Solution

The correct option is B 1.6
Stress induced
σ1=σ2=pr2t

σ1max=8×1002×1=400 MPa

σ1min=4×1002×1=200 MPa

σ2max=400 MPa
σ2min=200 MPa
σ1m=300 MPa
σ1a=100 MPa
σ2m=300 MPa
σ2a=100 MPa

Equivalent Stresses
σme=σ21m+σ22mσ1mσ2m

=3002+3002300×300

=300 MPa
Similarly,
σae=100 MPa
Goodman equation,
σaeSe+σmeSut=1n

100400+300800=1n

n = 1.6

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