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Question

# A thin symmetrical double convex lens of refractive index μ2=1.5 is placed between a medium of refractive index μ1=1.4 to the left and another medium of refractive index μ3=1.6 to the right. Then, the system behaves as.

A
A convex lens
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B
A concave lens
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C
A glass plate
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D
A convo concave lens
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Solution

## The correct option is C A glass plateFor first refracting Surface,For parallel beam of light, −μ1u+μ2v=μ2−1R−1.4−∞+1.5v=1.5−1.4RSo V = 15RFor Second refracting surface,−μ21.5R+μ3v′=μ3−μ2R−1.515R+1.6v′=1.6−1.5R∴v′=∞Hence, the combination behaves as glass plate.

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