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Question

A thin symmetrical double convex lens of refractive index μ2=1.5 is placed between a medium of refractive index μ1=1.4 to the left and another medium of refractive index μ3=1.6 to the right. Then, the system behaves as.

A
A convex lens
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B
A concave lens
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C
A glass plate
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D
A convo concave lens
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Solution

The correct option is C A glass plate
For first refracting Surface,
For parallel beam of light, μ1u+μ2v=μ21R
1.4+1.5v=1.51.4R

So V = 15R
For Second refracting surface,
μ21.5R+μ3v=μ3μ2R

1.515R+1.6v=1.61.5R
v=
Hence, the combination behaves as glass plate.

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