A thin uniform circular ring is rolling down an inclined plane of inclination 30∘ without slipping. Its linear acceleration along the inclined plane will be
A
g2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
g3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
g4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
g5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Cg4 a=gsinθ1+k2R2=gsin30∘1+1=g4[Ask2R2=1andθ=30∘]