A thin uniform rod has mass $1.2$ kg and length $4$ m. Find its moment of inertia a transverse axis through its center of mass.

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Solution

Moment of inertia of rod about its centre $I = \frac{M L^{2}}{12}$
So, $I = \frac{1.2 \times 4^{2}}{12} = 1.6 k g m^{2}$

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A thin uniform rod has mass 1.2kg and length 4m. Find its moment of inertia a transverse axis through its center of mass.

Moment of inertia of rod about its centre I=ML212So, I=1.2×4212=1.6 kg m2

A thin uniform rod has mass $1.2$ kg and length $4$ m. Find its moment of inertia a transverse axis through its center of mass.

Moment of inertia of rod about its centre $I = \frac{M L^{2}}{12}$
So, $I = \frac{1.2 \times 4^{2}}{12} = 1.6 k g m^{2}$