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Question

A thin uniform rod of mass m and length l is standing on a smooth horizontal surface. A slight disturbance causes the lower end to slip on the smooth surface. Find the velocity of centre of mass of the rod at the instant when it makes an angle 60 with the vertical.

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Solution

sin60=hL2
32=hL2
h=34L
Change in PE of COM = change in KE of COM
mg⎢ ⎢ ⎢L23L42⎥ ⎥ ⎥=12mv2
V= gL(13L)
Hence, solved.


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