Given conditions ⇒
Length of the wire = 21.7 cm
Radius of the Wire = 0.46 mm.
= 0.046 cm.
Area of the cross section = πr²
= 22/7 × (0.046)²
= 0.0066 cm².
∴ Volume of the wire = 0.0066 × 21.7
= 0.1443112 cm³
= 0.14 cm³ [since, the least numbers of the significant figures is 2.]
Hence, the volume of the wire is 0.14 cm³.