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Question

A three-digit number N leaves the same remainder upon dividing 68488 and 67516. How many possible values does N have?

A
8
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B
6
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C
5
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D
4
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Solution

The correct option is A 6
68488 and 67516 on dividing with N leaves same remainder.
N is a three digit number.

6848867516=972. On dividing by 972, 68488 and 67516 leaves the same remainder.

Now, three digit factors of 972 is 486,324,243,162,108.

So there are six values of N.

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