A three-member committee has to be formed from a group of 9 people. How many such distinct committees can be formed?

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Solution

The correct option is D 84
$^{9} C_{3} = \frac{9!}{6! \times 3!} = \frac{9 \times 8 \times 7}{6} = 84$

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A three-member committee has to be formed from a group of 9 people. How many such distinct committees can be formed?

The correct option is D 849C3=9!6!×3!=9×8×76=84

The correct option is D 84
$^{9} C_{3} = \frac{9!}{6! \times 3!} = \frac{9 \times 8 \times 7}{6} = 84$