A three phase diode rectifier has an input voltage of 480 V line-to-line at 50 Hz- It is connected to a load with resistance R - 25 - and inductance L - 50 mH- The apparent power flowing from source to load is Consider negligible ripple content in output-

For the given three phase diode rectifier, nbsp;the dc output voltage of bridge, nbsp; V_0 = 3V_m,L Lπ = 3√(2)×480π = 648.227 V The average load current, ...

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A three phase diode rectifier has an input voltage of 480 V (line-to-line) at 50 Hz. It is connected to a load with resistance $R = 25 Ω$ and inductance L = 50 mH. The apparent power flowing from source to load is (Consider negligible ripple content in output).

12.28 kVA

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39.60 kVA

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17.60 kVA

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28.90 kVA

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Solution

The correct option is C 17.60 kVA
For the given three phase diode rectifier, the dc output voltage of bridge,
$V_{0} = \frac{3 V_{m, L - L}}{π} = \frac{3 \sqrt{2} \times 480}{π} = 648.227 V$
The average load current,
$I_{0} = \frac{V_{0}}{R} = \frac{648.227}{25} = 25.929 A$
As ripple in output is negligible
$I_{0, r m s} = I_{0}$
The rms source current,
$I_{s, r m s} = (\frac{\sqrt{2}}{3}) I_{0, r m s} = \sqrt{\frac{2}{3}} \times 25.929 = 21.170 A$
The apparent power from source
$= (\sqrt{3}) (V_{L - L r m s}) (I_{s r m s})$
$= \sqrt{3} \times 480 \times 21.170$
$= 17.6 k V A$

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A three phase diode rectifier has an input voltage of 480 V (line-to-line) at 50 Hz. It is connected to a load with resistance R=25Ω and inductance L = 50 mH. The apparent power flowing from source to load is (Consider negligible ripple content in output).

A three phase diode rectifier has an input voltage of 480 V (line-to-line) at 50 Hz. It is connected to a load with resistance $R = 25 Ω$ and inductance L = 50 mH. The apparent power flowing from source to load is (Consider negligible ripple content in output).