A thrust of $20 N$ is acting on an area of $2 m^{2}$ . How much pressure is acting on the surface?

5 N m^{- 2}

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10 N m^{- 2}

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20 N m^{- 2}

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40 N m^{- 2}

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Solution

The correct option is B $10 N m^{- 2}$
Given:
Thrust, $F = 20 N$
Area, $A = 2 m^{2}$

Pressure is defined as the thrust acting per unit area.
$P = \frac{F}{A}$
$P = \frac{20 N}{2 m^{2}}$
$P = 10 N m^{- 2}$

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