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Question

A tie member of truss consist of two ISA 90×90×8 placed back to back connected to a gusset plate of 10 mm, has to carry a factored load of 250 kN. The grade of steel is Fe410 and one of the shear plane passes through thread.The number of bolts of diameter 18 mm of 4.6 class bolts required are _______.(Take kb=0.5)


  1. 4

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Solution

The correct option is A 4
Strength of bolt in double shear

Vdsb=(1+0.78)×π4×182×4003×1.25=83.68 kN

Strength of bolt in bearing

Vdpb=2.5kb.d.t.fuγmb
=2.5×0.5×18×10×4101.25=73.8kN

Bolt value,
=min(Vdsb,Vdpb)=73.8 kN

Number of bolts
=25073.8=3.38=4

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