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Question

A tiger running 100 m race, accelerates for one third time of the total time and then moves with uniform speed. Then find the total time taken by the tiger to run 100 m if the acceleration of the tiger is 8m/s2:

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Solution

3v0T=8
v0T=83
12×v0×T3+v02T3=100
v0T6+2v0T3=100
v0T+4v0T6=100
5v0T6=100
v0T=1008×6
v0T=120
v0T=83
v0Tv0T=120×38
T2=45
T=45
T=6.708s

988911_696596_ans_554289f5b27547099027b4c6dfcfa651.JPG

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