A time varying horizontal force (in Newton) F=8|sin(4πt)| is acting on a stationary block of mass 2kg as shown. Friction coefficient between the block and ground is μ=0.5 and g=10m/s2. Then resulting motion of the block will be:
A
It will oscillate
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B
It remains stationary
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C
It moves towards left
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D
It moves towards right
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Solution
The correct option is C It remains stationary Given, Applied variable horizontal force F=8|sin(4πt)|N Mass of block (m)=2kg Friction coefficient between block and ground μ=0.5 and g=10m/s2 We know that, maximum possible friction force, Ffrictionmax=μmg =0.5×2×10 =10N....(i) Maximum applied force (Fappliedmax)=8×1 =8N....(ii) [∵ maximum value of sinθ is 1] From equation (i) and (ii), we get ffrictionmax>fappliedmax So, the block will remain stationary.