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Question

A time varying horizontal force (in Newton) F=8|sin(4πt)| is acting on a stationary block of mass 2 kg as shown. Friction coefficient between the block and ground is μ=0.5 and g=10 m/s2. Then resulting motion of the block will be:
761234_4f23b5914b574aaaa80be998e4a9f8ad.jpg

A
It will oscillate
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B
It remains stationary
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C
It moves towards left
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D
It moves towards right
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Solution

The correct option is C It remains stationary
Given,
Applied variable horizontal force F=8|sin(4πt)|N
Mass of block (m)=2 kg
Friction coefficient between block and ground μ=0.5
and g=10m/s2
We know that,
maximum possible friction force, Ffriction max=μmg
=0.5×2×10
=10 N....(i)
Maximum applied force (Fapplied max)=8×1
=8 N....(ii)
[ maximum value of sinθ is 1]
From equation (i) and (ii), we get
ffriction max>fapplied max
So, the block will remain stationary.

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