A tiny positively charged particle is moving head-on towards a heavy nucleus .The distance of closest approach depends upon

The number of protons in the nucleus

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The number of nucleons in the nucleus

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The mass of the incident particle

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The charge and velocity of the incident particle

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Solution

The correct options are
A
The number of protons in the nucleus

C
The mass of the incident particle

D
The charge and velocity of the incident particle

The distance of closest approach is given by $r_{0}$ = $\frac{q z e}{2 π ϵ_{o} m v^{2}}$

q, m and v are charge, mass and velocity of incident particle and Z is the atomic number of the
target nucleus.

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