The correct options are
A The number of protons in the nucleus.
C The mass of the incident particle.
D The charge and velocity of the incident particle.
The distance of closest approach is given by, \(r_0 = \frac{1}{2 \pi \epsilon_0qZe}{mv^2}\)
q, m and v are charge, mass and velocity of incident particle and Z is the atomic number of the target nucleus.