A titanium sheet of 5.0 m thickness is cut by a wire-cut EDM process using a wire of 1.0 mm diameter. A uniform spark gap of 0.5 mm on both sides of the wire is maintained during the cutting operation. If the feed rate of the wire into the sheet is 20 mm/min. The material removal rate $i n m m^{3} / m i n$ will be

150

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200

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300

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400

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Solution

The correct option is B 200
Cross-section covered by wire :
$= (1 + 0.5 \times 2) \times 5 m m^{2}$
Feed rate = 20 mm/min
MRR rate:
$= 20 \times 5 \times 2 = 200 m m^{3} / m i n$

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The correct option is B 200Cross-section covered by wire : =(1+0.5×2)×5mm2 Feed rate = 20 mm/min MRR rate: =20×5×2=200mm3/min

The correct option is B 200
Cross-section covered by wire :
$= (1 + 0.5 \times 2) \times 5 m m^{2}$
Feed rate = 20 mm/min
MRR rate:
$= 20 \times 5 \times 2 = 200 m m^{3} / m i n$