Question

A titration is set up so that $35.0mL$ of $1.0MNaOH$ are titrated with $1.5MHCl$. How many milliliters of acid are needed to completely amount of base?

• A. $15.00mL$
• B. $35.00mL$
• C. $23.33mL$
• D. $58.33mL$
• E. $20.00mL$

Answer 1

Answer: (C)

$23.33mL$

$M1V1=M2V2$
$M1=$1.0 M = molarity of $NaOH$
$V1=$ $35.0$ mL = volume of $NaOH$
$M2=$ 1.5 M = molarity of $HCl$
$V2=$ volume of $HCl$
$1.0\times 35.0=1.5V2$
$V2=23.33$ mL
Hence, $23.33$ mL milliliters of acid are needed to completely amount of base.