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Question

(a) Tn = n find (i) Tn+1 (ii) T n−1

(b) If Tn = n2 − 1 find (i) Tn−2 (ii) Tn+1

(c) If Tn = 2n2 + 1 find the value of n if Tn = 73

(d) In a sequence Tn = 5 − 3n find (i) Tn+1 (ii) Tn+2

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Solution

(a)

(i) To find , substitute n + 1 in place of n in.

(ii) To find , substitute n 1 in place of n in.

(b)

(i) To find , substitute n 2 in place of n in.

(ii) To find, substitute n + 1 in place of n in.

(c)

It is given that .

Since n is a natural number, n = 6.

(d)

(i) To find, substitute n + 1 in place of n in.

(ii) To find, substitute n + 2 in place of n in.


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