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Question

A to E are
A : Cd(CH3COO)2
B : [Fe(CH3COO)]2+
C : CdS
D : [Cd(NH3)4]3+
E : [Cd(CN)4]2
If true enter 1, else enter 0.
203099_8b7eea5a5e2c463b942ff76d761e33c3.png

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Solution

The compound A is Cd(CH3COO)2
The compoundB is [Fe(CH3COO)]2+
The compoundC is CdS
The compoundD is [Cd(NH3)4]2+
The compoundE is [Cd(CN)4]2
Cd(CH3COO)2 reacts with neutral ferric chloride solution to give blood red
colour of [Fe(CH3COO)]2+
Cd(CH3COO)2+2FeCl32[Fe(CH3COO)]2++CdCl2+2Cl2
Cd(CH3COO)2 reacts with hydrogen sulphide in presence of HCl to form
yellow ppt of CdS
Cd(CH3COO)2+H2SHClCdS(yellow)+2CH3COO+2H+
CdS is soluble in nitric acid but insoluble in yellow ammonium sulphide (YAS).
Cd(CH3COO)2 reacts with aq ammonia to form white ppt which is soluble
in excess of ammonia to form [Cd(NH3)4]2+
Cd(CH3COO)2+4NH3[Cd(NH3)4]2++2CH3COO
Cd(CH3COO)2 reacts with aq KCN solution to form white ppt which is
soluble in excess of aq KCN to form [Cd(CN)4]2.
Cd(CH3COO)2+4KCN[Cd(CN)4]2+2CH3COO+4K+

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