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Question

# A toraid of non-ferromagnetic has core if inner radius24 cm and outer radius 25 cm , it has 3000 turns and carries a current of 11 A , then the magnetic field at a point in the internal cavity of toroid

A
Zero
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B
3×103T
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C
Infinity
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D
2.69×102T
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Solution

## The correct option is D 2.69×10−2TGiven: r1=24cm=0.24m r2=25cm=0.25m N=3000turns I=11ATo find: magnetic field in internal cavity,B=?Solution: As we know that, magnetic field in internal cavity is, B=μ0NI2πr ...(1)here, r is the mean radius.i.e. r=(r1+r2)/2 ==>r=(0.24+0.25)/2==>r=0.245mPut this in (1), we getB=2∗10−7∗3000∗110.245B=269.38∗10−4B=2.69∗10−2T

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