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Question

​​A torch bulb is rated 2.5V and 750mA. Two identical resistors, each of resistance 2 ohm , are connected in series and parallel to a battery of 12 V Calculate ratio of power consumed in two cases.

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Solution

IN SERIES

Total Resistance in Series = R₁ + R₂
= 2 + 2
= 4 Ohm

Potential Difference(V) = 12V
Current(I)= V/R
=12/4
=3Ampere
Power = VI
= 12*3
=36 Watts

(2) IN PARALLEL
1/R₁ + 1/R₂ = 1/Rₐ (Where Rₐ is the total resistance)
1/2 + 1/2 = 1/Rₐ
2/2 =1/Rₐ
1/1 = 1/Rₐ
1 Ohm = Rₐ

Voltage (V)= 12Volts
Current(I)= V/R
= 12 Ampere
Power= VI
= 12*12
= 144 Watt

Power in series : Power in Parallel
36 : 144
1 : 4


Regards

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