A torch bulb is rated $6 V$ and $750 m A$ . Calculate the energy consumed by the bulb in four hours.

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Solution

$E n e r g y = P o w e r * t i m e$

$= (V o l t a g e * C u r r e n t) * t i m e$

$E = 6 \times 750 m \times 4$

$= 18 W h r$

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A torch bulb is rated 6 V and 750 mA. Calculate the energy consumed by the bulb in four hours.

Energy=Power∗time=(Voltage∗Current)∗timeE=6×750m×4=18Whr

A torch bulb is rated $6 V$ and $750 m A$ . Calculate the energy consumed by the bulb in four hours.

$E n e r g y = P o w e r * t i m e$

$= (V o l t a g e * C u r r e n t) * t i m e$

$E = 6 \times 750 m \times 4$

$= 18 W h r$