A torque of $0.5 N m$ is required to drive a screw into a wooden frame with the help of a screw driver. If one of the two forces of couple produced by screw driver is $50 N$ , the width of the screw driver is:

0.5 c m

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0.75 c m

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1 c m

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1.5 c m

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Solution

The correct option is B $1 c m$
Let width be $x$ . So the torque due to couple is $2 \times 50 \times x / 2 = 50 x$
$50 x = 0.5 \Rightarrow x = 0.01 m = 1 c m$

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A torque of 0.5Nm is required to drive a screw into a wooden frame with the help of a screw driver. If one of the two forces of couple produced by screw driver is 50N, the width of the screw driver is:

The correct option is B 1cmLet width be x. So the torque due to couple is 2×50×x/2=50x50x=0.5⇒x=0.01m=1 cm

A torque of $0.5 N m$ is required to drive a screw into a wooden frame with the help of a screw driver. If one of the two forces of couple produced by screw driver is $50 N$ , the width of the screw driver is:

The correct option is B $1 c m$
Let width be $x$ . So the torque due to couple is $2 \times 50 \times x / 2 = 50 x$
$50 x = 0.5 \Rightarrow x = 0.01 m = 1 c m$