Question

A torque of $100N-m$ acting on a wheel at rest, rotates it through $200$ radian in $10s$. what is the moment of inertia of the wheel?

• A. $10kg-m^2$
• B. $15kg-m^2$
• C. $20kg-m^2$
• D. $25kg-m^2$

Answer 1

The correct option is D $25kg-m^2$

$s=\omega t+\frac{1}{2}\alpha t^2$

$200=0+\frac{1}{2}\alpha {10}^2$

$\alpha =4rad/s^2$

$T=I\alpha$

$100=I\times 4$

$I=25kg{m}^2$