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Question

A torque of 25 N m acts on a current carrying coil of area 5m2 in a magnetic field of induction 2Wb/m2 . The angle between normal to coil and magnetic induction is 30 .Then value of current is

A
0.4A
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B
0.5A
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C
400mA
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D
5A
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Solution

The correct option is D 5A
Given: τ=25Nm
A=5m2 \\area of coil
B=2Wb/m2
θ=30
To find: current,I=?
Solution: τ=IABsinθ
==>25=I52sin30
==>5=I2(1/2)
I=5Amp
hence,
The correct opt : D









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