CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Cathode Ray Experiment

A total charg...

Question

A total charge of 5 micro coulomb is distributed uniformly on the surface of the thin walled hemispherical cup. If the electric field strength at the centre of the hemisphere is 9*10'8 n/c, then the radius of the cup is?

Open in App

Solution

Suggest Corrections

thumbs-up

1

Similar questions

Q. A total charge of

5 μ c

is distributed uniformally on the surface of the thin walled semi spherical cup. If the electric field strength at the center of the semi sphere is

9 \times 10^{8} N C^{- 1}

, the radius of the cup is:

(\frac{1}{4 π \in_{0}} = 9 \times 10^{9} N m^{2} C^{- 2})

Q

coulombs is uniformly distributed throughout the volume of a solid hemisphere of radius

R

metres. Find the potential at centre

O

of the hemisphere (in volts):

Q

coulombs is uniformly distributed throughout the volume of a solid hemisphere of radius

R

meters. Then the potential at centre

O

of the base of the hemisphere in volts is

Q

is placed at the centre of a hemispherical surface of radius

R

. The flux of electric field due to charge

Q

, through the surface of hemisphere is

Q

' is placed at the centre of a hemispherical surface of radius '

R

'. The flux of electric field due to charge '

Q

' through the surface of hemisphere is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Cathode Ray Experiment

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Cathode Ray Experiment

Standard IX Chemistry

Join BYJU'S Learning Program

CrossIcon