Question

A tourist goes from $A$ to $B$ in the following manner. He goes straight $6$ mi, takes a right and travels $15$ mi and finally takes a left and travels $2$ mi to reach $B$. What is the difference between the distance covered, if he follows the above-mentioned path and if he goes directly from $A$ to $B$?

• A. $6$
• B. $8$
• C. $17$
• D. $23$

Answer 1

The correct option is A $6$

The tourist goes $6$ mi straight, $15$ mi after taking a right turn and again $2$ mi after taking a left.

Thus, overall he goes $15$ mi straight and $8$ mi towards the perpendicular direction.

Thus forming a triangle, we can find the straight line direct distance as $\sqrt{{15}^2+8^2}=17$ mi.

The distance he travelled $=6+15+2=23$ mi.

The difference between the two is therefore $6$ mi.