A tower HP standing vertically at the orthocentre H of a triangle ABC subtends an angle A at the vertex A of the triangle. The height of the tower is....
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Solution
The distance of orthocentre H from the vertices A, B, C are 2RcosA,2RcosB and 2RcosC where R is circum-radius of the triangle and asinA=2R AH=HPcotA or 2RcosA=hcotA or asinAcosA=hcotA∴h=a