Question

A tower is $100\sqrt{3}$ m high. Find the angle of elevation of its top from a point 100 m away from its foot.

• A. ${15}^{\circ }$
• B. ${45}^{\circ }$
• C. ${30}^{\circ }$
• D. ${60}^{\circ }$

Answer 1

The correct option is D

${60}^{\circ }$

Let the angle of elevation be $\theta$
$\Rightarrow \tan \theta =\frac{Perpendicular}{Base}$
​$\Rightarrow \tan \theta =\frac{100\sqrt{3}}{100}=\sqrt{3}$
​$\therefore \theta ={60}^{\circ }$