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Question

A tower is 1003 m tall. Find the angle of elevation of its top from a point 100 m away from its foot.


A

30

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B

60

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C

45

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D

15

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Solution

The correct option is B

60


Given:
Height of the tower = 1003 m
Distance from the tower = 100 m
To find:
Angle of elevation = θ
tanθ=Opposite sideAdjacent side=ABBC
tanθ=1003100=3
Hence, ​θ=60


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