A tower is 100√3 m tall. Find the angle of elevation of its top from a point 100 m away from its foot.
60∘
Given:
Height of the tower = 100√3 m
Distance from the tower = 100 m
To find:
Angle of elevation = θ
⇒tanθ=Opposite sideAdjacent side=ABBC
⇒tanθ=100√3100=√3
Hence, ∴θ=60∘