A tower stands at the centre of a circular park. If A and B are 2 points on the boundary of the park, such that AB = a meters subtends an angle of 60° at the foot of tower and angle of elevation of the top of the tower from A or B is 30 degrees, Find the height of the tower

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Q. A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB (= a) subtends an angle of

60^{\circ}

at the foot of the tower, and the angle of elevation of the top of the tower from A or B is

30^{\circ}

. The height of the tower is

Q. A vertical tower stands on a horizontal plane and from a point on the ground at a distance of

30

meters from the foot of the tower the angle of elevation

60^{0}

. The height of the tower is

(\sqrt{3} = 1.73)

Q. The angles of elevation of the top of a tower standing on a horizontal plane from two points on a line passing through the foot of the tower at distance

a

and

b

respectively are complementary angles. Prove that the height of the tower is

\sqrt{a b}

. If the line joining the two points subtends and angle

θ

at the top of the tower, show that

sin θ = \frac{(a - b)}{(a + b)}

A tower subtends an angle of $30^{\circ}$ at a point on the same level as its foot. At a second point 'h' meters above the first point, the angle of depression of the foot of the tower is $60^{\circ}$ . The height of the tower is:

Q. A tower subtends and angle 60 at a point A in the plane of its base and the angle of depression of the foot of the tower at a point 10 meters just above A is 30. The height of the tower is

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