Question

A tower stands vertically one the ground. From a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top of the tower is ${60}^o$. What is the height of the tower?

Answer 1

Here, $AB$ is the height of a tower.

$\Rightarrow$ $CB=20m$

$\Rightarrow$ Now, $\tan {60}^o=\frac{AB}{CB}$

$\Rightarrow$ $\sqrt{3}=\frac{AB}{20}$

$\therefore$ $AB=20\sqrt{3}m$

$\therefore$ Height of a tower is $20\sqrt{3}m$.