A tower subtends an angle of 30∘ at a point on the same level as its foot. At a second point 'h' meters above the first point, the angle of depression to the foot of the first tower is 60∘. The height of the tower is:
h/3 m
Let the height of tower be H
In triangle ABC,
tan30∘ = ABAC = HAC .................................. 1
In triangle ADC,
tan60∘ = CDAC = hAC........................................2
Divide 1 by 2, we get tan30∘tan60∘ = Hh
H = h3