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Question

A tower subtends an angle of 30 at a point on the same level as its foot. At a second point 'h' meters above the first point, the angle of depression to the foot of the first tower is 60. The height of the tower is:


A

h/2 m

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B

h/3 m

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C

√3h

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D

h/√3

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Solution

The correct option is B

h/3 m


Let the height of tower be H

In triangle ABC,

tan30 = ABAC = HAC .................................. 1

In triangle ADC,

tan60 = CDAC = hAC........................................2

Divide 1 by 2, we get tan30tan60 = Hh

H = h3


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