Question

A tower $T_1$ of height $60$ m is located exactly opposite to a tower $T_2$ of height $80$ m on a straight road. From the top of $T_1$, if the angle of elevation of the top of $T_2$ is ${60}^{\circ }$ then the width (in m) of the road between the feet of the towers $T_1$ and $T_2$ is?

Answer 1

Height of $T_1=60m$

Height of $T_2=80m$

Angle of elevation ${60}^{\circ }$

$⟹\tan 60=\frac{80-60}{\text{Distance}}\sqrt{3}=\frac{20}{\text{Distance}}\text{Distance}=\frac{20}{\sqrt{3}}$