A toy car initially moving with a uniform velocity of $18 k m p h$ comes to a stop in $2 s$ . Find the retardation of the car in SI units.

2.5 m s^{- 2}

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5 m s^{- 2}

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9 m s^{- 2}

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36 m s^{- 2}

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Solution

The correct option is A $2.5 m s^{- 2}$
Initial velocity $= 18 k m p h = \frac{18 \times 1000}{60 \times 60} m s^{- 1} = 5 m s^{- 1}$
Final velocity $= 0$
Time $= 2 s$
$∴$ Retardation $= \frac{5 - 0}{2} m s^{- 2} = 2.5 m s^{- 2}$

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A toy car initially moving with a uniform velocity of 18kmph comes to a stop in 2s. Find the retardation of the car in SI units.

The correct option is A 2.5ms−2Initial velocity =18kmph=18×100060×60ms−1=5ms−1Final velocity =0Time =2s∴ Retardation =5−02ms−2=2.5ms−2

A toy car initially moving with a uniform velocity of $18 k m p h$ comes to a stop in $2 s$ . Find the retardation of the car in SI units.

The correct option is A $2.5 m s^{- 2}$
Initial velocity $= 18 k m p h = \frac{18 \times 1000}{60 \times 60} m s^{- 1} = 5 m s^{- 1}$
Final velocity $= 0$
Time $= 2 s$
$∴$ Retardation $= \frac{5 - 0}{2} m s^{- 2} = 2.5 m s^{- 2}$