A toy car is at rest, and a force of 70 N is applied to it in rightwards direction. If the frictional force between the toy and the floor is 20 N, determine the net force acting on the toy car.

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Solution

Let's consider the forces acting on the toy car along its direction of motion as positive.
Given:
Applied force, $F_{a}$ = + 70 N (rightwards)
Frictional force, $F_{f}$ = -20 N (leftwards)
(As friction always acts in the direction opposite to that of the motion of the object)
$F_{N e t}$ = $F_{a}$ + $F_{f}$
$F_{N e t}$ = + 70 N + (-20 N)
$F_{N e t}$ = + 50 N
Therefore, the net force acting on the toy car is 50 N (rightwards).

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