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Question

# A toy car of mass 500 g travels with a uniform velocity of 25 cmsâˆ’1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Calculate the distance which the car travels after the brakes are applied.

A
1.25cm
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B
125m
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C
1.25m
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D
25m
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Solution

## The correct option is C 1.25mGiven that this toy car has a velocity of 25cm/sec which is also equal to 0.25m/sec. Here toy car is retarded confirming it has final velocity 0m/sec and it came to rest within 10seconds. We know that acceleration is nothing but rate of change of velocity.a=v−uta=0−0.2510a=0.025m/s2.v2−u2a=s0.252−02=2×0.025×ss=1.25mHence displacement is 1.25m.

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